CH_3-CH_2-CH=CH_2 xrightarrow[CCl_4]{HCl} X x | vedclass

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(B) The reaction sequence is as follows: $1.$ Addition of $HCl$ to $CH_3-CH_2-CH=CH_2$ (but-$1$-ene) follows Markovnikov's rule to give $X = CH_3-CH_2

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$CH_3-CH=CH-CH_3$

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(B) The reaction sequence is as follows: $1.$ Addition of $HCl$ to $CH_3-CH_2-CH=CH_2$ (but-$1$-ene) follows Markovnikov's rule to give $X = CH_3-CH_2-CHCl-CH_3$ ($2$-chlorobutane). $2.$ Reaction of $X$ with $Aq. NaOH$ (nucleophilic substitution) gives $Y = CH_3-CH_2-CH(OH)-CH_3$ (butan-$2$-ol). $3.$ Dehydration of $Y$ with $Conc. H_3PO_4$ and heat follows Zaitsev's rule to give the more stable,more substituted alkene as the major product,which is $Z = CH_3-CH=CH-CH_3$ (but-$2$-ene).

$CH_3-CH_2-CH=CH_2$ $\xrightarrow[CCl_4]{HCl} X$ $\xrightarrow{Aq. NaOH} Y$ $\xrightarrow[\Delta]{Conc. H_3PO_4} Z$
The major product $Z$ is:

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$CH_3-CH_2-CH=CH_2$ $\xrightarrow[CCl_4]{HCl} X$ $\xrightarrow{Aq. NaOH} Y$ $\xrightarrow[\Delta]{Conc. H_3PO_4} Z$ The major product $Z$ is: