The reaction is given by:(1-hydroxycyclopenta | vedclass

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(C) The starting material is $1$-hydroxycyclopentane-$1,1$-dicarboxylic acid.When this compound is heated with an oxidizing agent like $K_2Cr_2O_7$,it

Vedclass · Accepted Answer

Cyclopentanone

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(C) The starting material is $1$-hydroxycyclopentane-$1,1$-dicarboxylic acid.When this compound is heated with an oxidizing agent like $K_2Cr_2O_7$,it undergoes oxidation of the secondary alcohol group to a ketone,followed by decarboxylation of the gem-dicarboxylic acid group.Specifically,the $1$-hydroxy group is oxidized to a ketone,forming $1$-oxocyclopentane-$1,1$-dicarboxylic acid.This $\beta$-keto acid (or specifically,a gem-dicarboxylic acid derivative) is unstable upon heating and undergoes decarboxylation (loss of $CO_2$) to yield cyclopentanone.

The reaction is given by:
($1$-hydroxycyclopentane$-1,1-$dicarboxylic acid) $\xrightarrow[\Delta ]{K_2Cr_2O_7}\,(P)$
Product $(P)$ will be:

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The reaction is given by:($1$-hydroxycyclopentane$-1,1-$dicarboxylic acid) $\xrightarrow[\Delta ]{K_2Cr_2O_7}\,(P)$Product $(P)$ will be: