The reaction sequence is as follows: CH(COOK) | vedclass

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(A) $1$. The electrolysis of an aqueous solution of potassium maleate (or fumarate) is a Kolbe electrolysis reaction.$2$. The reaction is: $CH(COOK)=C

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$CH_3-CH=O$

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(A) $1$. The electrolysis of an aqueous solution of potassium maleate (or fumarate) is a Kolbe electrolysis reaction.$2$. The reaction is: $CH(COOK)=CH(COOK) + 2H_2O \xrightarrow{	ext{electrolysis}} CH \equiv CH + 2CO_2 + H_2 + 2KOH$.$3$. Thus,$X$ is acetylene $(CH \equiv CH)$.$4$. The hydration of acetylene in the presence of $Hg^{2+}$ and $dil. H_2SO_4$ (Kucherov reaction) yields acetaldehyde $(CH_3CHO)$.$5$. The reaction is: $CH \equiv CH + H_2O$ $\xrightarrow{Hg^{2+}/H_2SO_4} [CH_2=CH-OH]$ $ightarrow CH_3-CH=O$.$6$. Therefore,$Y$ is $CH_3-CH=O$.

The reaction sequence is as follows:
$CH(COOK)=CH(COOK)_{(aq)}$ $\xrightarrow{\text{electrolysis}} X$ $\xrightarrow[Hg^{2+}]{dil. H_2SO_4} Y$; $Y$ is

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The reaction sequence is as follows: $CH(COOK)=CH(COOK)_{(aq)}$ $\xrightarrow{\text{electrolysis}} X$ $\xrightarrow[Hg^{2+}]{dil. H_2SO_4} Y$; $Y$ is