......... is a unit of volume.

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Volume is defined as the amount of space occupied by a three-dimensional object.In the International System of Units $(SI)$,the base unit of lengt

Vedclass · Accepted Answer

$m^3$

Vedclass · Answer

(B) Volume is defined as the amount of space occupied by a three-dimensional object.In the International System of Units $(SI)$,the base unit of length is the meter $(m)$.Since volume is calculated as the product of three dimensions (length $	imes$ width $	imes$ height),its unit is the cube of the unit of length.Therefore,the unit of volume is $m 	imes m 	imes m = m^3$.- $m$ is a unit of length.- $m^2$ is a unit of area.- $cm^2$ is also a unit of area.Thus,the correct option is $B$.

Part $I$	Part $II$
$1.$ Volume of a cuboid	$a.$ $\frac{1}{3} \pi r^{2} h$
$2.$ Volume of a cone	$b.$ $\pi r^{2} h$
$3.$ Volume of a cylinder	$c.$ $\frac{4}{3} \pi r^{3}$
$4.$ Volume of a sphere	$d.$ $lbh$

Similar Questions

The radii of a frustum of a cone are $10 \, cm$ and $7 \, cm$. If its height is $4 \, cm$,its curved surface area is $\dots \dots \dots \pi \, cm^2$.

The $TSA$ of a hemisphere with radius $10 \, cm$ is $\ldots \ldots \ldots \, cm^{2}$. (in $\pi$)

The radii of a frustum of a cone are $9\, cm$ and $3\, cm$. If its height is $8\, cm$,find its curved surface area and volume. $(\pi=3.14)$

The curved surface area $(CSA)$ of a cone is $\ldots \ldots$

Which of the following correctly matches the information given in Part $I$ and Part $II$?

Part $I$ Part $II$

$1.$ Volume of a cuboid $a.$ $\frac{1}{3} \pi r^{2} h$

$2.$ Volume of a cone $b.$ $\pi r^{2} h$

$3.$ Volume of a cylinder $c.$ $\frac{4}{3} \pi r^{3}$

$4.$ Volume of a sphere $d.$ $lbh$

Vedclass Test Series

Exam Paper Generator

Online Exam Module