Identify the product of the following reaction:
$C_6H_6 + CO + HCl \xrightarrow{AlCl_3} \text{Product}$
$C_6H_6 + CO + HCl \xrightarrow{AlCl_3} \text{Product}$
- AEthylbenzene
- BBenzyl alcohol
- CBenzaldehyde
- DBenzoyl chloride
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Similar Questions
Match the reactants in column $-I$ with the reaction conditions in column $-II$ to find the corresponding products in column $-III$.
Column $-I$ (Reactant) Column $-II$ (Reaction Condition) Column $-III$ (Product) $A$. $CH_3CN + C_6H_5MgBr$ $i$. $Ether, H_3O^+$ $p$. Benzaldehyde $B$. $Benzene + CH_3COCl$ $ii$. $Hg^{2+}, H_2SO_4, H_2O$ $q$. Acetophenone $C$. $Toluene$ $iii$. $Anhydrous AlCl_3$ $r$. Propiophenone $D$. $Phenyl ethyne$ $iv$. $x. Cl_2, hv$; $y. H_2O, 373 \ K$ $s$. Acetaldehyde
| Column $-I$ (Reactant) | Column $-II$ (Reaction Condition) | Column $-III$ (Product) |
|---|---|---|
| $A$. $CH_3CN + C_6H_5MgBr$ | $i$. $Ether, H_3O^+$ | $p$. Benzaldehyde |
| $B$. $Benzene + CH_3COCl$ | $ii$. $Hg^{2+}, H_2SO_4, H_2O$ | $q$. Acetophenone |
| $C$. $Toluene$ | $iii$. $Anhydrous AlCl_3$ | $r$. Propiophenone |
| $D$. $Phenyl ethyne$ | $iv$. $x. Cl_2, hv$; $y. H_2O, 373 \ K$ | $s$. Acetaldehyde |
Difficult
View SolutionRosenmund reduction cannot be used for the preparation of
Medium
View SolutionIn the reaction sequence $CHCl_3$ $\xrightarrow{Air/hv} x$ $\xrightarrow[Excess]{C_6H_6 / Anhy. AlCl_3} y$,$y$ will be
Difficult
View SolutionThe reaction is given as follows:
$Ph-CO-N(CH_3)(OCH_3) + 2CH_3MgBr \xrightarrow{H_3O^+} (P)$
Product $(P)$ is:
$Ph-CO-N(CH_3)(OCH_3) + 2CH_3MgBr \xrightarrow{H_3O^+} (P)$
Product $(P)$ is:
Medium
View SolutionWhat is the major product of the following reaction? $CH_3-C \equiv N$ $\xrightarrow[Et_2O]{CH_3MgI}$ $\xrightarrow{H_3O^{+}}$
Medium
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