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(B) The reaction is a nucleophilic aromatic substitution $(S_NAr)$ reaction.The substrate is $1$-fluoro-$2$-chloro-$4$-nitrobenzene.The nitro group $(

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$2-$chloro$-4-$nitrophenol

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(B) The reaction is a nucleophilic aromatic substitution $(S_NAr)$ reaction.The substrate is $1$-fluoro-$2$-chloro-$4$-nitrobenzene.The nitro group $(-NO_2)$ is a strong electron-withdrawing group that activates the ortho and para positions towards nucleophilic attack.In this molecule,the fluorine atom is at the para position with respect to the $-NO_2$ group,and the chlorine atom is at the meta position with respect to the $-NO_2$ group.Nucleophilic substitution occurs most readily at the position para to the electron-withdrawing group because the intermediate carbanion (Meisenheimer complex) is stabilized by resonance with the $-NO_2$ group.Furthermore,fluorine is a better leaving group than chlorine in $S_NAr$ reactions due to its high electronegativity,which stabilizes the transition state of the nucleophilic attack.Therefore,the $OH^-$ ion attacks the carbon atom attached to the fluorine atom,leading to the displacement of the fluoride ion.The final product is $2$-chloro-$4$-nitrophenol.

Predict the major product of the following reaction:
$1$-fluoro-$2$-chloro-$4$-nitrobenzene $\xrightarrow[(ii) H^+]{(i) NaOH}$ Product

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Predict the major product of the following reaction:$1$-fluoro-$2$-chloro-$4$-nitrobenzene $\xrightarrow[(ii) H^+]{(i) NaOH}$ Product