5 persons will live in a tent. If each person | vedclass

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(A) Total floor area required for $5$ persons $= 16 	imes 5 = 80\, m^2$.Total volume of air required for $5$ persons $= 100 	imes 5 = 500\, m^3$.The

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$18.75$

Vedclass · Answer

(A) Total floor area required for $5$ persons $= 16 	imes 5 = 80\, m^2$.Total volume of air required for $5$ persons $= 100 	imes 5 = 500\, m^3$.The volume of a cone is given by the formula $V = \frac{1}{3} 	imes A 	imes h$,where $A$ is the base area and $h$ is the height.For the smallest tent,we set the base area $A = 80\, m^2$ and the volume $V = 500\, m^3$.Substituting these values into the formula: $500 = \frac{1}{3} 	imes 80 	imes h$.Solving for $h$: $h = \frac{500 	imes 3}{80} = \frac{1500}{80} = \frac{150}{8} = 18.75\, m$.

$5$ persons will live in a tent. If each person requires $16\, m^2$ of floor area and $100\, m^3$ space for air,then the height of the cone of smallest size to accommodate these persons would be? (in $m$)

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