A woman is a carrier for hemophilia (having o | vedclass

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(C) Let $X^H$ be the gene for normal blood clotting and $X^h$ be the gene for hemophilia. Let $X^C$ be the gene for normal vision and $X^c$ be the gen

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$50\%$ hemophilic,color-blind sons and $50\%$ hemophilic sons.

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(C) Let $X^H$ be the gene for normal blood clotting and $X^h$ be the gene for hemophilia. Let $X^C$ be the gene for normal vision and $X^c$ be the gene for color blindness. The woman is a carrier for hemophilia $(X^H X^h)$ and also carries the color blindness gene on one $X$ chromosome. Assuming the genes are linked,her genotype is $X^{Hc} X^h$ (where $c$ is the color blindness allele). The normal man has the genotype $X^{HC} Y$. When they cross: $1$. $X^{Hc} X^h 	imes X^{HC} Y$ $2$. Offspring genotypes: $X^{Hc} X^{HC}$ (Carrier daughter),$X^{Hc} Y$ (Hemophilic and color-blind son),$X^h X^{HC}$ (Carrier daughter),$X^h Y$ (Hemophilic son). Thus,the sons will be $50\%$ hemophilic and color-blind,and $50\%$ hemophilic.

Column $I$	Column $II$
$(a)$ Sickle cell anaemia	$(x)$ Homogentisic acid
$(b)$ Alkaptonuria	$(y)$ Melanin pigments are absent
$(c)$ Albinism	$(z)$ More amount of phenylalanine
$(d)$ Phenylketonuria	$(w)$ Defective haemoglobin

$A$ woman is a carrier for hemophilia (having one gene on each $X$ chromosome) and also carries one gene for color blindness on one $X$ chromosome. She marries a normal man. What will be the phenotype of their offspring?

Similar Questions

Color blindness is a ..... trait.

Alkaptonuria is caused due to

Match the columns:

Column $I$ Column $II$

$(a)$ Sickle cell anaemia $(x)$ Homogentisic acid

$(b)$ Alkaptonuria $(y)$ Melanin pigments are absent

$(c)$ Albinism $(z)$ More amount of phenylalanine

$(d)$ Phenylketonuria $(w)$ Defective haemoglobin

Consider the following human disorders: $i$. Hemophilia,$ii$. Down's syndrome,$iii$. Cystic fibrosis,$iv$. Color blindness,$v$. Night blindness. Which of these represent Mendelian disorders?

Which of the following is controlled by a recessive gene in humans?

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