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(B) Color blindness is an $X$-linked recessive disorder.Let $X^C$ be the allele for color blindness and $X$ be the normal allele.The man is normal-vis

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(B) Color blindness is an $X$-linked recessive disorder.Let $X^C$ be the allele for color blindness and $X$ be the normal allele.The man is normal-visioned,so his genotype is $XY$. Since his father was color-blind $(X^CY)$,he inherited his $Y$ chromosome from his father and his $X$ chromosome from his mother. Thus,his genotype is $XY$.The woman's father was color-blind $(X^CY)$,so she must have inherited the $X^C$ allele from him. Since she is not mentioned as color-blind,she is a carrier with the genotype $X^CX$.Cross: $XY$ (man) $	imes$ $X^CX$ (woman).Possible offspring genotypes: $XX, X^CX, XY, X^CY$.The female offspring genotypes are $XX$ (normal) and $X^CX$ (carrier).Neither of the female offspring genotypes is color-blind $(X^CX^C)$.Therefore,the probability of their daughter being color-blind is $0\%$.

$A$ normal-visioned man,whose father was color-blind,marries a woman whose father was also color-blind. What is the probability that their first child,a daughter,will be color-blind (in $\%$)?

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