In DNA,the unequal nitrogenous bases will pri | vedclass

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(A) According to $Chargaff's$ rule,in a double-stranded $DNA$ molecule,the amount of adenine $(A)$ is equal to thymine $(T)$,and the amount of guanine

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Single-stranded

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(A) According to $Chargaff's$ rule,in a double-stranded $DNA$ molecule,the amount of adenine $(A)$ is equal to thymine $(T)$,and the amount of guanine $(G)$ is equal to cytosine $(C)$. Therefore,the ratio $(A+T)/(G+C)$ is constant for a species. If the nitrogenous bases are unequal (i.e.,$A+T 
eq G+C$),it indicates that the $DNA$ molecule is single-stranded,as the base-pairing rules of $Watson$ and $Crick$ do not apply to single-stranded structures.

In $DNA$,the unequal nitrogenous bases will primarily be ...

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