What is the length of one full turn of the he | vedclass

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(A) In the structure of $\beta-DNA$ (Watson-Crick model),the helix makes a complete turn every $3.4 \, nm$ (or $34 \, \mathring{A}$). Each turn consis

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$3.4$

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(A) In the structure of $\beta-DNA$ (Watson-Crick model),the helix makes a complete turn every $3.4 \, nm$ (or $34 \, \mathring{A}$). Each turn consists of $10$ base pairs. The distance between two adjacent base pairs is $0.34 \, nm$ (or $3.4 \, \mathring{A}$). Therefore,the length of one full turn is $10 	imes 0.34 \, nm = 3.4 \, nm$.

What is the length of one full turn of the helix in $\beta-DNA$ (in $, nm$)?

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