The following table shows the population data | vedclass

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(C) Species diversity is determined by the number of species present in a given area (species richness).$1$. Area $A$: Species present are $a, b, c, d

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$D$

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(C) Species diversity is determined by the number of species present in a given area (species richness).$1$. Area $A$: Species present are $a, b, c, d, f, g, h, j$. Total = $8$ species.$2$. Area $B$: Species present are $a, c, e, f, h, i, j$. Total = $7$ species.$3$. Area $C$: Species present are $a, b, c, d, e, f, g, h, i, j$. Total = $10$ species.$4$. Area $D$: Species present are $a, b, c, d, e, f, g, h, i, j$. Total = $10$ species.Comparing the species richness, both $C$ and $D$ have $10$ species. However, in ecological studies, if the number of species is equal, we look at the evenness or the total population distribution. In this specific dataset, $D$ shows a more balanced distribution across all $10$ species compared to $C$, which has some very low values (e.g., $0.48$). Thus, $D$ is considered to have higher diversity.

Area and Number of Habitats	Species and their numbers (in thousands)
	$a, b, c, d, e, f, g, h, i, j$
$A (11)$	$2.3, 1.2, 0.52, 6.0, -, 3.1, 1.1, 9.2, -, 10.3$
$B (11)$	$10.2, -, 0.62, -, 1.5, 3.0, -, 8.2, 1.1, 11.2$
$C (13)$	$11.3, 0.9, 0.48, 2.4, 1.4, 4.2, 0.8, 8.4, 2.2, 4.1$
$D (12)$	$3.2, 10.2, 11.1, 4.8, 0.4, 3.3, 0.8, 7.3, 11.3, 2.1$

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