2BF_3 + 6NaH xrightarrow{450 K} X_{(g)} + 6N | vedclass

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(B) The given reaction is: $2BF_3 + 6NaH \xrightarrow{450 \ K} B_2H_6 + 6NaF$. Thus,$X$ is diborane $(B_2H_6)$.$1$. $B_2H_6$ undergoes hydrolysis to f

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Back bonding is present in $X$.

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(B) The given reaction is: $2BF_3 + 6NaH \xrightarrow{450 \ K} B_2H_6 + 6NaF$. Thus,$X$ is diborane $(B_2H_6)$.$1$. $B_2H_6$ undergoes hydrolysis to form boric acid $(H_3BO_3)$,which is a weak monobasic acid. This statement is correct.$2$. In $B_2H_6$,there is no back bonding; it is an electron-deficient molecule with $3c-2e$ bonds. This statement is incorrect.$3$. In the structure of $B_2H_6$,the two boron atoms and the four terminal hydrogen atoms lie in the same plane. Thus,the maximum number of atoms in one plane is $6$. This statement is correct.$4$. $B_2H_6$ burns in $O_2$ to form $B_2O_3$ (boron sesquioxide). This statement is correct.

$2BF_3 + 6NaH \xrightarrow{450 \ K} X_{(g)} + 6NaF$. Which of the following statements is \textbf{Incorrect} for $X$?

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