10 , text{mole} of ferric oxalate is oxidised | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The chemical formula for ferric oxalate is $Fe_2(C_2O_4)_3$. In the oxidation process,$Fe^{2+}$ is not present (it is $Fe^{3+}$),so only the oxala

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) The chemical formula for ferric oxalate is $Fe_2(C_2O_4)_3$. In the oxidation process,$Fe^{2+}$ is not present (it is $Fe^{3+}$),so only the oxalate ion $(C_2O_4^{2-})$ is oxidised to $CO_2$. The half-reaction for the oxidation of oxalate is: $C_2O_4^{2-} ightarrow 2CO_2 + 2e^-$. Since there are $3$ moles of $C_2O_4^{2-}$ in $1$ mole of $Fe_2(C_2O_4)_3$,the total electrons released per mole of ferric oxalate is $3 	imes 2 = 6 \, e^-$. For $10 \, 	ext{moles}$ of ferric oxalate,total electrons released $= 10 	imes 6 = 60 \, e^-$. The reduction half-reaction for $MnO_4^-$ in acidic medium is: $MnO_4^- + 8H^+ + 5e^- ightarrow Mn^{2+} + 4H_2O$. To balance the electrons,the number of moles of $MnO_4^-$ required is: $x = \frac{60}{5} = 12$.

$10 \, \text{mole}$ of ferric oxalate is oxidised by $x \, \text{mole}$ of $MnO_4^-$ in acidic medium. The value of $x$ is

Similar Questions

In the reaction $SnCl_2(excess) + HgCl_2 \rightarrow A + SnCl_4$,'$A$' is

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$CaSO_3(s) + H_2SO_4(aq) \longrightarrow CaSO_4(s) + SO_2(g) + H_2O(l)$

Which of the following are redox changes?
$(i)$ Hydrolysis of $XeF_2$
$(ii)$ Thermal decomposition of $Ag_2CO_3$
$(iii)$ Reaction of $Al$ with $NaOH$
$(iv)$ Hydrolysis of $PCl_5$
$(v)$ Reaction of $NaCl$ with conc. $H_2SO_4$
Correct options are:

Which of the following can act both as an oxidizing and a reducing agent?

Which of the following reactions will lead to a redox reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module