NH_3 + CO_2 + H_2O to AA + H_2O + CO_2 to BB | vedclass

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(D) The given reactions represent the Solvay process for the manufacture of sodium carbonate $(Na_2CO_3)$:$1$. $2NH_3 + CO_2 + H_2O 	o (NH_4)_2CO_3$

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$B = (NH_4)_2C_2O_4$

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(D) The given reactions represent the Solvay process for the manufacture of sodium carbonate $(Na_2CO_3)$:$1$. $2NH_3 + CO_2 + H_2O 	o (NH_4)_2CO_3$ $(A)$$2$. $(NH_4)_2CO_3 + H_2O + CO_2 	o 2NH_4HCO_3$ $(B)$$3$. $NH_4HCO_3 + NaCl 	o NaHCO_3$ $(C)$ + $NH_4Cl$$4$. $2NaHCO_3 \xrightarrow{\Delta} Na_2CO_3$ $(D)$ + $H_2O + CO_2$Comparing these with the options:$A = (NH_4)_2CO_3$ (Correct)$B = NH_4HCO_3$ (Option $D$ says $B = (NH_4)_2C_2O_4$,which is incorrect)$C = NaHCO_3$ (Correct)$D = Na_2CO_3$ (Correct)Therefore,the incorrect statement is $B = (NH_4)_2C_2O_4$.

$NH_3 + CO_2 + H_2O \to A$
$A + H_2O + CO_2 \to B$
$B + NaCl \to C + NH_4Cl$
$C \xrightarrow{\Delta} D + H_2O + CO_2$
Identify the incorrect statement.

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$NH_3 + CO_2 + H_2O \to A$$A + H_2O + CO_2 \to B$$B + NaCl \to C + NH_4Cl$$C \xrightarrow{\Delta} D + H_2O + CO_2$Identify the incorrect statement.