The IUPAC name of the following compound is : | vedclass

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Question

(B) $1$. Identify the principal functional group: The compound is a cyclic alkene. The double bond gets priority in numbering.$2$. Number the ring: St

Vedclass · Accepted Answer

$2-$Ethyl-$1, 1-$dimethyl-$2-$cyclohexene

Vedclass · Answer

(B) $1$. Identify the principal functional group: The compound is a cyclic alkene. The double bond gets priority in numbering.$2$. Number the ring: Start numbering from the double bond carbons such that the substituents get the lowest possible locants. Assign $C-1$ and $C-2$ to the double bond carbons.$3$. If we assign $C-1$ to the carbon with the ethyl group and $C-2$ to the carbon with the two methyl groups,the locants are $1-$ethyl and $2, 2-$dimethyl.$4$. If we assign $C-1$ to the carbon with the two methyl groups and $C-2$ to the carbon with the ethyl group,the locants are $1, 1-$dimethyl and $2-$ethyl.$5$. According to the $IUPAC$ rule of lowest locant set,$(1, 1, 2)$ is preferred over $(1, 2, 2)$.$6$. Therefore,the correct numbering gives the name $2-$Ethyl-$1, 1-$dimethylcyclohex-$2-$ene (or $2-$Ethyl-$1, 1-$dimethyl-$2-$cyclohexene).

The $IUPAC$ name of the following compound is :-

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