$\mathop {\lim }\limits_{x \to 0} \frac{{x\sqrt {{y^2} - {{(y - x)}^2}} }}{{{{(\sqrt {8xy - 4{x^2}} + \sqrt {8xy} )}^3}}}$ is equal to

  • A
    $\frac{1}{4}$
  • B
    $\frac{1}{2}$
  • C
    $\frac{1}{{2\sqrt 2 }}$
  • D
    $\frac{1}{{128y}}$

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