$H_2S$ is more acidic than $H_2O$,due to

Ozone is prepared by passing silent electric discharge through oxygen. In this reaction,

Which of the following diagrams is correct for the change of sulphur compounds?

Although oxygen is more electronegative than sulfur,$H_2S$ is acidic while $H_2O$ is neutral. This is because ..........

Why does $O_{3}$ act as a powerful oxidising agent?

Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$ : Both rhombic and monoclinic sulphur exist as $S_8$ while oxygen exists as $O_2$.
Reason $(R)$ : Oxygen forms $p \pi-p \pi$ multiple bonds with itself and other elements having small size and high electronegativity like $C, N$,which is not possible for sulphur.
In the light of the above statements,choose the most appropriate answer from the options given below: