The order H_2O

Question

(D) $1$. Boiling point: The boiling point of $H_2O$ is $100 \ ^\circ C$ $(373 \ K)$,while the boiling point of $H_2O_2$ is $150 \ ^\circ C$ $(423 \ K)

Vedclass · Accepted Answer

All of the above are correct

Vedclass · Answer

(D) $1$. Boiling point: The boiling point of $H_2O$ is $100 \ ^\circ C$ $(373 \ K)$,while the boiling point of $H_2O_2$ is $150 \ ^\circ C$ $(423 \ K)$. Thus,$H_2O $2$. Acidic nature: $H_2O_2$ is a stronger acid than $H_2O$ because the $O-H$ bond in $H_2O_2$ is more polar due to the electron-withdrawing effect of the second oxygen atom,and the resulting hydroperoxide ion $(HO_2^-)$ is more stable than the hydroxide ion $(OH^-)$. Thus,$H_2O $3$. Dipole moment: The dipole moment of $H_2O$ is $1.85 \ D$,while the dipole moment of $H_2O_2$ is $2.13 \ D$. Thus,$H_2O Since all statements are correct,the correct option is $D$.

Column $-A$	Column $-B$
$(1).$ $H_2O_2$	$(p).$ As moderator
$(2).$ $D_2O$	$(q).$ As fuel
$(3).$ Liquid $H_2$	$(r).$ For to make hard water soft
$(4).$ Zeolite	$(s).$ As disinfectant

The order $H_2O < H_2O_2$ is correct for which of the following properties?

Similar Questions

Match the correct option from Column $-A$ and Column $-B.$

Column $-A$ Column $-B$

$(1).$ $H_2O_2$ $(p).$ As moderator

$(2).$ $D_2O$ $(q).$ As fuel

$(3).$ Liquid $H_2$ $(r).$ For to make hard water soft

$(4).$ Zeolite $(s).$ As disinfectant

Sodium oxalate on heating with conc. $H_2SO_4$ gives

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