CH_3-CHO xrightarrow[OH^{-}]{HCN} (A) xrighta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Acetaldehyde reacts with $HCN$ in the presence of a base $(OH^{-})$ to form acetaldehyde cyanohydrin $(A)$,which is $CH_3-CH(OH)-CN$. Partial hydr

Vedclass · Accepted Answer

$CH_3-CH(OH)-CONH_2$

Vedclass · Answer

(D) Acetaldehyde reacts with $HCN$ in the presence of a base $(OH^{-})$ to form acetaldehyde cyanohydrin $(A)$,which is $CH_3-CH(OH)-CN$. Partial hydrolysis of the nitrile group $(-CN)$ in $(A)$ yields an amide group $(-CONH_2)$,resulting in the formation of $CH_3-CH(OH)-CONH_2$ $(B)$. Reaction: $CH_3-CHO + HCN$ $\xrightarrow{OH^{-}} CH_3-CH(OH)-CN (A)$ $\xrightarrow{H_2O/H^{+}} CH_3-CH(OH)-CONH_2 (B)$

$CH_3-CHO$ $\xrightarrow[OH^{-}]{HCN} (A)$ $\xrightarrow{\text{Partial Hydrolysis}} (B)$. Product $B$ is:

Similar Questions

Methyl ketone group is identified by

What product is formed when benzaldehyde reacts with methylamine?

Identify the final product of the following reaction sequence:
$o$-Phthalaldehyde $\xrightarrow{\text{OH}^-} A$ $\xrightarrow{\text{H}^+, \Delta} ?$

$A$ compound gives a positive test with $I_2/NaOH$ and is extracted from benzene by $NaHSO_3$. It may be:

Reduction of which compound gives an optically active alcohol?

Vedclass Test Series

Exam Paper Generator

Online Exam Module