$CH_3-CH_2-C(=O)-OCH_3 + 2CH_3MgBr \to A \xrightarrow[\Delta]{H^+} B$
The product $B$ is:

  • A
    $CH_3-C(CH_3)=CH-CH_3$
  • B
    $CH_3-CH(CH_3)-CH=CH_2$
  • C
    $CH_3-C(OH)(CH_3)-CH_2-CH_3$
  • D
    $CH_3-C(CH_3)_2-CH_2-OH$

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