20 mL of 0.5 N HCl and 35 mL of 0.1 N N | vedclass

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(D) Calculate the milliequivalents $(meq)$ of each reactant:$meq 	ext{ of } HCl = N 	imes V 	ext{ (in } mL) = 0.5 	imes 20 = 10 \ meq$.$meq 	ext{

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turn methyl orange solution orange red.

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(D) Calculate the milliequivalents $(meq)$ of each reactant:$meq 	ext{ of } HCl = N 	imes V 	ext{ (in } mL) = 0.5 	imes 20 = 10 \ meq$.$meq 	ext{ of } NaOH = N 	imes V 	ext{ (in } mL) = 0.1 	imes 35 = 3.5 \ meq$.Since $meq 	ext{ of } HCl > meq 	ext{ of } NaOH$,the acid is in excess.$meq 	ext{ of } HCl 	ext{ remaining} = 10 - 3.5 = 6.5 \ meq$.Because the resulting solution contains excess acid,it is acidic.Methyl orange is an indicator that turns orange-red in an acidic medium.

$20 \ mL$ of $0.5 \ N \ HCl$ and $35 \ mL$ of $0.1 \ N \ NaOH$ are mixed. The resulting solution will

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