1. KClO_3 xrightarrow{Delta }2. XeF_2 xrighta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. $2KClO_3 \xrightarrow{\Delta} 2KCl + 3O_2$ (Produces $O_2$)$2$. $2XeF_2 + 2H_2O \longrightarrow 2Xe + 4HF + O_2$ (Produces $O_2$)$3$. $6XeF_4

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) $1$. $2KClO_3 \xrightarrow{\Delta} 2KCl + 3O_2$ (Produces $O_2$)$2$. $2XeF_2 + 2H_2O \longrightarrow 2Xe + 4HF + O_2$ (Produces $O_2$)$3$. $6XeF_4 + 12H_2O \longrightarrow 4Xe + 2XeO_3 + 24HF + 3O_2$ (Produces $O_2$)$4$. $2PbO_2 \xrightarrow{\Delta} 2PbO + O_2$ (Produces $O_2$)$5$. $XeF_6 + 3H_2O \longrightarrow XeO_3 + 6HF$ (Does not produce $O_2$)Total processes yielding $O_2$ are $1, 2, 3,$ and $4$. Hence,the total count is $4$.

$1$. $KClO_3 \xrightarrow{\Delta }$
$2$. $XeF_2 \xrightarrow{H_2O}$
$3$. $XeF_4 \xrightarrow{H_2O}$
$4$. $PbO_2 \xrightarrow{\Delta }$
$5$. $XeF_6 \xrightarrow{H_2O}$
In how many of the above processes,$O_2$ will be one of the products?

Similar Questions

$X_2$ is used in the refining of $Ti$ metal by the van Arkel method. $Y_2$ does not liberate $O_2$ from water and does not form $HY$ and $HOY$ with water. $X_2$ and $Y_2$ are respectively:

The correct order of acidity of the following hydra acids is:

$SO_2$ acts as a temporary bleaching agent,while $Cl_2$ acts as a permanent bleaching agent. Why?

Which of the following gives chlorine upon heating?

Explain the electron gain enthalpy values of elements of the $17^{\text{th}}$ group. Give reasons and explain.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$1$. $KClO_3 \xrightarrow{\Delta }$$2$. $XeF_2 \xrightarrow{H_2O}$$3$. $XeF_4 \xrightarrow{H_2O}$$4$. $PbO_2 \xrightarrow{\Delta }$$5$. $XeF_6 \xrightarrow{H_2O}$In how many of the above processes,$O_2$ will be one of the products?