In the reaction sequence: $C_6H_5NH_2$ $\xrightarrow{CHCl_3/KOH, \Delta} (X)$ $\xrightarrow{LiAlH_4/H_2O} (Y)$,the product $(Y)$ is:

  • A
    $C_6H_5NHCH_3$
  • B
    $C_6H_5CH_2NH_2$
  • C
    $C_6H_5NHCHO$
  • D
    $C_6H_5NC$

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Similar Questions

Given below are two statements:
Statement $I$ : The $NH_2$ group in Aniline is ortho and para directing and a powerful activating group.
Statement $II$ : Aniline does not undergo Friedel-Craft's reaction (alkylation and acylation).
In the light of the above statements,choose the most appropriate answer from the options given below :

Identify the reagent used for the conversion of aniline to phenol from the following.

$(A)$ $\xrightarrow[(1) \text{ excess } CH_3I/K_2CO_3, (2) \text{ } Ag_2O/H_2O, (3) \text{ } \Delta]{} (B)$ $\xrightarrow[(i) \text{ excess } CH_3I/K_2CO_3, (ii) \text{ } Ag_2O, (iii) \text{ } \Delta]{} H_2C=CH-CH(CH_3)-CH=CH_2$. Identify $(A)$.

Which of the following compounds is $NOT$ formed as an intermediate product in the Hofmann bromamide degradation reaction?

Which of the following will not give Hoffmann bromamide reaction?

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