CH_3-CH_2-OH xrightarrow[Delta]{Cl_2 / OH^{-} | vedclass

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(C) $1.$ $CH_3-CH_2-OH$ reacts with $Cl_2 / OH^{-}$ to undergo haloform reaction,yielding $CHCl_3$ (Compound $A$).$2.$ $2CHCl_3$ reacts with $Ag$ powd

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$CH_3-CHO$

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(C) $1.$ $CH_3-CH_2-OH$ reacts with $Cl_2 / OH^{-}$ to undergo haloform reaction,yielding $CHCl_3$ (Compound $A$).$2.$ $2CHCl_3$ reacts with $Ag$ powder upon heating to produce acetylene,$CH \equiv CH$ (Compound $B$).$3.$ $CH \equiv CH$ undergoes hydration in the presence of $1\% HgSO_4$ and $20\% H_2SO_4$ (Kucherov's reaction) to form acetaldehyde,$CH_3-CHO$ (Compound $C$).

$CH_3-CH_2-OH$ $\xrightarrow[\Delta]{Cl_2 / OH^{-}} A$ $\xrightarrow[\Delta]{Ag} B$ $\xrightarrow[1\% HgSO_4]{20\% H_2SO_4, H_2O} C$ Compound '$C$' is:

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