Identify the product A in the following react | vedclass

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(B) $MnO_2$ (Manganese dioxide) is a selective oxidizing agent that specifically oxidizes allylic and benzylic alcohols to their corresponding aldehyd

Vedclass · Accepted Answer

The product $A$ is a benzene ring with a $-OH$ group,a $-CHO$ group,and a $-CH(CH_2CH_3)CHO$ group.

Vedclass · Answer

(B) $MnO_2$ (Manganese dioxide) is a selective oxidizing agent that specifically oxidizes allylic and benzylic alcohols to their corresponding aldehydes or ketones.In the given substrate,the $-CH(CH_2CH_3)CHO$ group contains an aldehyde,and the $-COOH$ group is a carboxylic acid. The $-OH$ group is phenolic. $MnO_2$ does not oxidize phenolic $-OH$ groups or carboxylic acids under standard conditions.However,if the substrate was intended to have an allylic or benzylic alcohol,$MnO_2$ would oxidize it to an aldehyde. Given the options,the reaction likely involves the selective oxidation of a benzylic alcohol to an aldehyde. Option $B$ represents the oxidation of a benzylic alcohol to an aldehyde while leaving the phenolic $-OH$ and the other aldehyde group intact.

Identify the product $A$ in the following reaction:
$\text{Substrate} \xrightarrow{MnO_2} A$
(The substrate is a benzene ring with a $-OH$ group,a $-COOH$ group,and a $-CH(CH_2CH_3)CHO$ group attached to it.)

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Identify the product $A$ in the following reaction:$\text{Substrate} \xrightarrow{MnO_2} A$(The substrate is a benzene ring with a $-OH$ group,a $-COOH$ group,and a $-CH(CH_2CH_3)CHO$ group attached to it.)