CH_3COOH xrightarrow[Delta ]{NH_3} X xrightar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction sequence is as follows:$1.$ $CH_3COOH + NH_3 \xrightarrow{\Delta} CH_3CONH_2 (X)$ (Acetamide)$2.$ $CH_3CONH_2 + NaOBr \xrightarrow{}

Vedclass · Accepted Answer

$CH_3-O-CH_3$

Vedclass · Answer

(C) The reaction sequence is as follows:$1.$ $CH_3COOH + NH_3 \xrightarrow{\Delta} CH_3CONH_2 (X)$ (Acetamide)$2.$ $CH_3CONH_2 + NaOBr \xrightarrow{} CH_3NH_2 (Y)$ (Methylamine - Hoffmann Bromamide Degradation)$3.$ $CH_3NH_2 + NaNO_2 + HCl \xrightarrow{} CH_3OH$ (Methanol) or $CH_3OCH_3$ (Dimethyl ether) depending on conditions. Given the options,$Z$ is $CH_3-O-CH_3$.

$CH_3COOH$ $\xrightarrow[\Delta ]{NH_3} X$ $\xrightarrow{NaOBr} Y$ $\xrightarrow{NaNO_2 + HCl} Z$. What is $Z$?

Similar Questions

In the given reaction sequence,what is $Z$?
Aniline $\xrightarrow{CH_3COCl} X$ $\xrightarrow{Br_2/AlBr_3} Y$ $\xrightarrow{H_3O^+} Z$

$p$-aminophenol reacts with one equivalent of acetyl chloride in the presence of pyridine to give mainly

In the following reaction,
$C_6H_5NHCOC_6H_5 \xrightarrow[conc. \ H_2SO_4]{conc. \ HNO_3} X$
the structure of the major product $X$ is

Among the following compounds,the increasing order of their basic strength is

The reaction of aniline with chloroform and alcoholic $KOH$ yields .....

Vedclass Test Series

Exam Paper Generator

Online Exam Module