Br_2 + 2X^{-} to 2Br^{-} + X_2Cl_2 + 2Y^{-} t | vedclass

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(C) The reactions follow the principle that a stronger halogen (higher oxidation potential) can displace a weaker halogen from its halide salt.For the

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$X_2 = Cl_2$

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(C) The reactions follow the principle that a stronger halogen (higher oxidation potential) can displace a weaker halogen from its halide salt.For the first reaction: $Br_2 + 2X^{-} 	o 2Br^{-} + X_2$,$Br_2$ can displace $I^{-}$ to form $I_2$ $(X_2 = I_2)$. It cannot displace $Cl^{-}$ or $F^{-}$. Thus,$X_2$ can be $I_2$.For the second reaction: $Cl_2 + 2Y^{-} 	o 2Cl^{-} + Y_2$,$Cl_2$ can displace $Br^{-}$ to form $Br_2$ $(Y_2 = Br_2)$ or $I^{-}$ to form $I_2$ $(Y_2 = I_2)$.Option $C$ states $X_2 = Cl_2$. If $X_2 = Cl_2$,the reaction would be $Br_2 + 2Cl^{-} 	o 2Br^{-} + Cl_2$. This is impossible because $Br_2$ is a weaker oxidizing agent than $Cl_2$ and cannot displace $Cl^{-}$ from its salt.Therefore,the incorrect match is $X_2 = Cl_2$.

$Br_2 + 2X^{-} \to 2Br^{-} + X_2$
$Cl_2 + 2Y^{-} \to 2Cl^{-} + Y_2$
The incorrect match regarding the above reactions is:

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$Br_2 + 2X^{-} \to 2Br^{-} + X_2$$Cl_2 + 2Y^{-} \to 2Cl^{-} + Y_2$The incorrect match regarding the above reactions is: