H - C equiv C - C equiv C - CH_3Compare the b | vedclass

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(C) Bond $a$ is formed by the overlap of two $sp$ hybridized carbon atoms ($sp-sp$ bond).Bond $b$ is formed by the overlap of an $sp$ hybridized carbo

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$b > a$

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(C) Bond $a$ is formed by the overlap of two $sp$ hybridized carbon atoms ($sp-sp$ bond).Bond $b$ is formed by the overlap of an $sp$ hybridized carbon atom and an $sp^3$ hybridized carbon atom ($sp-sp^3$ bond).The bond length depends on the $s$-character of the hybrid orbitals involved.Greater $s$-character leads to a smaller atomic radius and shorter bond length.The $sp$ orbital has $50\%$ $s$-character,while the $sp^3$ orbital has $25\%$ $s$-character.Therefore,the $sp-sp$ bond $(a)$ has more $s$-character than the $sp-sp^3$ bond $(b)$.Consequently,bond $a$ is shorter than bond $b$,which means $b > a$.

$H - C \equiv C - C \equiv C - CH_3$
Compare the bond lengths $a$ and $b$.

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$H - C \equiv C - C \equiv C - CH_3$Compare the bond lengths $a$ and $b$.