$I$ and $II$ are geometrical isomers of each other because

  • A
    $l_1 = l_2$
  • B
    $l_1 > l_2$
  • C
    $l_2 > l_1$
  • D
    $l_1$ and $l_2$ cannot be compared

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Similar Questions

Identify the type of isomerism exhibited by the following structures:
$H_3C-CH=CH-CH_3$ (cis-but$-2-$ene) and $H_3C-CH=CH-CH_3$ (trans-but$-2-$ene).

Which of the following shows geometrical isomers?
$(a)$ $CH_2=CHCl$
$(b)$ $CH_3CH=CH_2$
$(c)$ $CHCl=CHCl$
$(d)$ $(CH_3)_2C=CHC_2H_5$

Which of the following compounds will show $cis-trans$ isomerism?
$(i)$ $(CH_3)_2C=CH-C_2H_5$
$(ii)$ $CH_2=CBr_2$
$(iii)$ $C_6H_5CH=CH-CH_3$
$(iv)$ $CH_3CH=CClCH_3$

Between $cis$ and $trans$ isomers,which has a higher dipole moment? Explain with an example.

Which of the following compounds will show geometrical isomerism?

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