$Ph-CH(Br)-CH_2-CH_2-Br \xrightarrow[\Delta]{Zn-Cu} \text{Product}$. The product of the above reaction is:

  • A
    $Ph-CH=CH-CH_2-Br$
  • B
    Phenylcyclopropane
  • C
    $Ph-CHBr-CH=CH_2$
  • D
    $Ph-C \equiv C-CH_3$

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