1,2-text{dichloroethane} + NaSCH_2CH_2SNa to | vedclass

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(A) The reaction between $1,2-	ext{dichloroethane}$ $(ClCH_2CH_2Cl)$ and disodium ethane$-1,2-$dithiolate $(NaSCH_2CH_2SNa)$ is a nucleophilic substi

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$1,4-$dithiane

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(A) The reaction between $1,2-	ext{dichloroethane}$ $(ClCH_2CH_2Cl)$ and disodium ethane$-1,2-$dithiolate $(NaSCH_2CH_2SNa)$ is a nucleophilic substitution reaction.The sulfur atoms in the dithiolate act as nucleophiles and attack the carbon atoms of $1,2-	ext{dichloroethane}$,displacing the chloride ions.This leads to the formation of a six-membered heterocyclic ring known as $1,4-	ext{dithiane}$ $(C_4H_8S_2)$ and the byproduct $2NaCl$.The reaction is: $ClCH_2CH_2Cl + NaSCH_2CH_2SNa 	o C_4H_8S_2 + 2NaCl$.Thus,the product $(P)$ is $2NaCl$.

$1,2-\text{dichloroethane} + NaSCH_2CH_2SNa \to C_4H_8S_2 + (P)$
Unknown product $(P)$ of the above reaction is

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$1,2-\text{dichloroethane} + NaSCH_2CH_2SNa \to C_4H_8S_2 + (P)$Unknown product $(P)$ of the above reaction is