CH_3Cl to CH_4Above conversion can be achieve | vedclass

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(D) $1$. $CH_3Cl \xrightarrow{Zn/H^{+}} CH_4$ (Reduction by metal-acid).$2$. $CH_3Cl \xrightarrow{LiAlH_4} CH_4$ (Reduction by strong reducing agent).

Vedclass · Accepted Answer

all of these

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(D) $1$. $CH_3Cl \xrightarrow{Zn/H^{+}} CH_4$ (Reduction by metal-acid).$2$. $CH_3Cl \xrightarrow{LiAlH_4} CH_4$ (Reduction by strong reducing agent).$3$. $CH_3Cl$ $\xrightarrow{Mg, 	ext{ dry ether}} CH_3MgCl$ $\xrightarrow{H_2O} CH_4$ (Grignard reagent formation followed by hydrolysis).Since all three methods successfully convert chloromethane to methane,the correct option is $D$.

$CH_3Cl \to CH_4$
Above conversion can be achieved by

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$CH_3Cl \to CH_4$Above conversion can be achieved by