(A) + Cl_2 xrightarrow{hv} text{monochloro pr | vedclass

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(B) The free radical chlorination of an alkane $(A)$ is a chain reaction that can lead to polychlorination if $Cl_2$ is present in excess. To maximize

Vedclass · Accepted Answer

Reactant $(A)$ must be added in excess

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(B) The free radical chlorination of an alkane $(A)$ is a chain reaction that can lead to polychlorination if $Cl_2$ is present in excess. To maximize the yield of the monochloro product,the concentration of the alkane $(A)$ must be kept high relative to $Cl_2$. By adding reactant $(A)$ in excess,the probability of a $Cl^{\bullet}$ radical colliding with an unreacted molecule of $(A)$ is significantly higher than colliding with a monochloro product molecule,thereby minimizing further chlorination.

$(A) + Cl_2 \xrightarrow{hv} \text{monochloro product}$. To maximize the yield of the monochloro product in the above reaction:

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