CH_3-CH_2-CH_2-CH_2-C(CH_3)_2-CH_2-OH xrighta | vedclass

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(C) The reaction is an acid-catalyzed dehydration of an alcohol. The mechanism involves the following steps:$1$. Protonation of the hydroxyl group to

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$CH_3-CH_2-CH_2-CH_2-CH=C(CH_3)_2$

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(C) The reaction is an acid-catalyzed dehydration of an alcohol. The mechanism involves the following steps:$1$. Protonation of the hydroxyl group to form a good leaving group $(-OH_2^+)$.$2$. Loss of water to form a primary carbocation: $CH_3-CH_2-CH_2-CH_2-C(CH_3)_2-CH_2^+$.$3$. Rearrangement: To form a more stable carbocation,an $n$-butyl shift occurs,resulting in a tertiary carbocation: $(CH_3)_2C^+-CH_2-CH_2-CH_2-CH_2-CH_3$.$4$. Elimination: Loss of a proton from the adjacent carbon leads to the formation of the most stable alkene (major product) according to Saytzeff's rule.$5$. The major product is $CH_3-CH_2-CH_2-CH_2-CH=C(CH_3)_2$.

$CH_3-CH_2-CH_2-CH_2-C(CH_3)_2-CH_2-OH \xrightarrow[\Delta]{H^{+}} (A) \text{ (major)}$. Product $(A)$ is

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