Ph-CO-OH + CH_3-O^{18}-H xrightarrow{H^{+}} ( | vedclass

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(B) In the Fischer esterification reaction,the oxygen atom of the alcohol is incorporated into the ester product,while the hydroxyl group $(-OH)$ of t

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$X = Ph-CO-O^{18}-CH_3$,Esterification reaction

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(B) In the Fischer esterification reaction,the oxygen atom of the alcohol is incorporated into the ester product,while the hydroxyl group $(-OH)$ of the carboxylic acid is eliminated as water.Specifically,the $O^{18}$ isotope from the methanol $(CH_3-O^{18}H)$ ends up in the ester linkage.Therefore,the product $(X)$ is $Ph-CO-O^{18}-CH_3$.This process is an esterification reaction.

$Ph-CO-OH + CH_3-O^{18}-H \xrightarrow{H^{+}} (X) + H_2O$. Identify $(X)$.

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