$Ph-COOH$ $\xrightarrow{SOCl_2} (A)$ $\xrightarrow{H_2, Pd-BaSO_4} (B)$. Product $(B)$ is:

  • A
    $Ph-CHO$
  • B
    $Ph-CH_2-OH$
  • C
    $Ph-CH_2-Cl$
  • D
    $Ph-CH=CH_2$

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