Ph-CH_3 xrightarrow{CrO_2Cl_2} (A) xrightarro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction sequence is as follows:$1$. $Ph-CH_3$ reacts with $CrO_2Cl_2$ (Etard reaction) to form benzaldehyde $(A)$,which is $Ph-CHO$.$2$. $Ph-

Vedclass · Accepted Answer

$Ph-CO_2^-$

Vedclass · Answer

(B) The reaction sequence is as follows:$1$. $Ph-CH_3$ reacts with $CrO_2Cl_2$ (Etard reaction) to form benzaldehyde $(A)$,which is $Ph-CHO$.$2$. $Ph-CHO$ reacts with concentrated $KOH$ (Cannizzaro reaction). Since benzaldehyde has no $\alpha$-hydrogen,it undergoes disproportionation to form benzyl alcohol $(Ph-CH_2OH)$ and potassium benzoate $(Ph-COO^-K^+)$.$3$. Thus,product $(B)$ is the benzoate ion,$Ph-COO^-$.

$Ph-CH_3$ $\xrightarrow{CrO_2Cl_2} (A)$ $\xrightarrow{conc. KOH} Ph-CH_2OH + (B)$
Product $(B)$ of the above reaction is:

Similar Questions

Which of the following is most reactive towards the addition reaction of hydrogen cyanide to form the corresponding cyanohydrin?

Which among the following reagents cannot be used for the above interconversion? The reaction involves the reduction of a ketone group $(>C=O)$ to a methylene group $(-CH_2-)$.

Paraldehyde is

Among the following,the compounds which can be reduced with formaldehyde and conc. $aq.$ $KOH$ are $.....$

Acetaldehyde and acetone can be distinguished by

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Ph-CH_3$ $\xrightarrow{CrO_2Cl_2} (A)$ $\xrightarrow{conc. KOH} Ph-CH_2OH + (B)$Product $(B)$ of the above reaction is: