In the given reaction,A will be:text{Cyclopro | vedclass

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(A) The reaction of primary aliphatic amines with nitrous acid $(HNO_2)$ proceeds via the formation of a highly unstable diazonium salt,which rapidly

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Cyclopropylmethanol

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(A) The reaction of primary aliphatic amines with nitrous acid $(HNO_2)$ proceeds via the formation of a highly unstable diazonium salt,which rapidly loses nitrogen gas to form a carbocation intermediate.In the case of cyclopropylmethylamine,the initial carbocation formed is the cyclopropylmethyl cation. This cation is in equilibrium with the cyclobutyl cation and the homoallyl cation due to ring expansion and rearrangement processes.These carbocations then react with water (the nucleophile) to form the corresponding alcohols. The major product $(A)$ formed in this reaction is cyclopropylmethanol,which accounts for $48\%$ of the product mixture.Therefore,$A$ is cyclopropylmethanol.

In the given reaction,$A$ will be:
$\text{Cyclopropylmethylamine} \xrightarrow{HNO_2} (A) + \text{cyclobutanol} (47\%) + \text{but-3-en-1-ol} (5\%)$

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In the given reaction,$A$ will be:$\text{Cyclopropylmethylamine} \xrightarrow{HNO_2} (A) + \text{cyclobutanol} (47\%) + \text{but-3-en-1-ol} (5\%)$