$R-CONH_2 + xNaOH + Br_2 \to R-NH_2 + 2NaBr + Na_2CO_3 + H_2O$
The number of moles of $NaOH$ used in the above Hoffmann bromamide reaction is:

Identify $Z$ in the following reaction:

Aniline when treated with conc. $HNO_3$ gives:

Chloroform when treated with aniline and alcoholic $KOH$ gives:

$A$ compound $X$ with formula $C_4H_{11}N$ reacts with $HNO_2$ to liberate nitrogen and produce compound $Y$. The compound $Y$ on treatment with $I_2 / NaOH$ produces a sodium salt of a carboxylic acid. The compound $X$ is

$9.3 \ g$ of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product '$P$'. The mass of product '$P$' obtained is $26.4 \ g$. The percentage yield is $......... \ \%$.