$R-CONH_2 + xNaOH + Br_2 \to R-NH_2 + 2NaBr + Na_2CO_3 + H_2O$
The number of moles of $NaOH$ used in the above Hoffmann bromamide reaction is:
The number of moles of $NaOH$ used in the above Hoffmann bromamide reaction is:
- A$3$
- B$4$
- C$5$
- D$6$
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