In the given carbylamine reaction,the value of $x$ (moles of $KOH$ consumed) is:
$C_6H_5NH_2 + CHCl_3 + xKOH \rightarrow C_6H_5NC + 3KCl + 3H_2O$
$C_6H_5NH_2 + CHCl_3 + xKOH \rightarrow C_6H_5NC + 3KCl + 3H_2O$
- A$1$
- B$2$
- C$3$
- D$4$
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