p-Toluidine reacts with benzene diazonium chl | vedclass

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Question

(A) $p$-Toluidine reacts with benzene diazonium chloride to form a diazoamino compound $(p-CH_3-C_6H_4-NH-N=N-Ph)$.This compound exists in tautomeric

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) $p$-Toluidine reacts with benzene diazonium chloride to form a diazoamino compound $(p-CH_3-C_6H_4-NH-N=N-Ph)$.This compound exists in tautomeric equilibrium with the aminoazo form $(p-CH_3-C_6H_4-N=N-NH-Ph)$.On boiling with $aq. H_2SO_4$ (acidic hydrolysis),both tautomers undergo cleavage.The diazoamino form cleaves to give $p$-toluidine and benzene diazonium salt (which further decomposes to phenol and nitrogen,but the question asks for the products of the cleavage of the formed compound).Looking at the provided reaction scheme,the hydrolysis of the diazoamino form yields $p$-toluidine and toluene (via reduction/decomposition pathways in specific conditions),while the aminoazo form yields $p$-toluidine and $p$-cresol.Counting the distinct organic products formed across the pathways shown in the reaction scheme: $p$-toluidine,toluene,and $p$-cresol are the distinct organic products.Thus,the total number of products is $3$.

List-$I$	List-$II$
$a$. Gabriel synthesis	$i$. Benzaldehyde
$b$. Kolbe synthesis	$ii$. Ethers
$c$. Williamson synthesis	$iii$. Primary amines
$d$. Etard reaction	$iv$. Salicylic acid

$p$-Toluidine reacts with benzene diazonium chloride to form a compound,which on boiling with $aq. H_2SO_4$ gives ........ products.

Similar Questions

Identify $C$ in the following reaction sequence:
$Cyclohexanone$ $\xrightarrow[\text{Alkaline medium}]{HCN} A$ $\xrightarrow{LiAlH_4} B$ $\xrightarrow{NaNO_2/HCl} C$

Match List-$I$ with List-$II$ :

List-$I$ List-$II$

$a$. Gabriel synthesis $i$. Benzaldehyde

$b$. Kolbe synthesis $ii$. Ethers

$c$. Williamson synthesis $iii$. Primary amines

$d$. Etard reaction $iv$. Salicylic acid

Choose the correct answer from the options given below :

Consider the following sequence of reactions to produce major product $(A)$. Molar mass of product $(A)$ is $........... \ g \ mol^{-1}$. (Given molar mass in $g \ mol^{-1}$ of $C : 12, H : 1, O : 16, Br : 80, N : 14, P : 31$)

Predict the stereochemistry of the product when a $d$ and $l$-amine mixture reacts with an $l$-acid.

$E \xleftarrow{KOH/Br_2} D \xleftarrow{H_2O_2/OH^{-} \atop (Partial \ Hydrolysis)} C \xleftarrow{NaCN} C_2H_5-Cl$ $\xrightarrow{AgCN} A$ $\xrightarrow{LiAlH_4} B$
What is the relationship between $B$ and $E$?

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