The IUPAC name of the given compound CH_2=CH- | vedclass

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(B) $1$. The given compound is $CH_2=CH-CH_2-CH_2-C \equiv CH$. $2$. The longest carbon chain contains $6$ carbon atoms,so the parent alkane is hexane

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Hex$-1-$en$-5-$yne

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(B) $1$. The given compound is $CH_2=CH-CH_2-CH_2-C \equiv CH$. $2$. The longest carbon chain contains $6$ carbon atoms,so the parent alkane is hexane. $3$. According to $IUPAC$ rules,when both double and triple bonds are present,numbering is done such that the double bond gets the lower number if there is a choice. $4$. Numbering from the left: $C_1=C_2-C_3-C_4-C_5 \equiv C_6$. The double bond is at position $1$ and the triple bond is at position $5$. $5$. The name is constructed as $Hex-1-en-5-yne$.

The $IUPAC$ name of the given compound $CH_2=CH-CH_2-CH_2-C \equiv CH$ is:

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