H - Nmathop { - - - }limits^{(I)} Nmathop { | vedclass

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(A) The structure of hydrogen azide $(HN_3)$ is represented by resonance hybrids.The resonance structures are:$H-N=N^{+}=N^{-} \leftrightarrow H-N^{-}

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$I  2$

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(A) The structure of hydrogen azide $(HN_3)$ is represented by resonance hybrids.The resonance structures are:$H-N=N^{+}=N^{-} \leftrightarrow H-N^{-}-N^{+}\equiv N$In the first structure,bond $(I)$ is a double bond and bond $(II)$ is a double bond.In the second structure,bond $(I)$ is a single bond and bond $(II)$ is a triple bond.Considering the resonance hybrid,the bond order of bond $(I)$ (between $N_1$ and $N_2$) is between $1$ and $2$,i.e.,$The bond order of bond $(II)$ (between $N_2$ and $N_3$) is between $2$ and $3$,i.e.,$> 2$.Therefore,the bond order of $(I)$ is $ 2$.

$H - N\mathop { - - - }\limits^{(I)} N\mathop { - - - }\limits^{(II)} N$
In hydrogen azide,the bond orders of bonds $(I)$ and $(II)$ are . . . . . .

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Assertion : Energy of resonance hybrid is equal to the average of energies of all canonical forms.
Reason : Resonance hybrid cannot be presented by a single structure.

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$H - N\mathop { - - - }\limits^{(I)} N\mathop { - - - }\limits^{(II)} N$In hydrogen azide,the bond orders of bonds $(I)$ and $(II)$ are . . . . . .