C_2H_5Br xrightarrow{AgCN} X xrightarrow{text | vedclass

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Question

(A) The reaction of ethyl bromide with $AgCN$ produces ethyl isocyanide as the major product because $AgCN$ is a covalent compound.$C_2H_5Br + AgCN \r

Vedclass · Accepted Answer

Ethyl methyl amine

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(A) The reaction of ethyl bromide with $AgCN$ produces ethyl isocyanide as the major product because $AgCN$ is a covalent compound.$C_2H_5Br + AgCN \rightarrow C_2H_5NC (X) + AgBr$Reduction of isocyanides with reducing agents like $LiAlH_4$ or catalytic hydrogenation yields secondary amines.$C_2H_5NC + 4[H] \rightarrow C_2H_5NHCH_3 (Y)$Thus,$Y$ is ethyl methyl amine.

$C_2H_5Br$ $\xrightarrow{AgCN} X$ $\xrightarrow{\text{Reduction}} Y$. Here $Y$ is

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