CH_3-CH_2-C(Ph)(OH)-CH_3 can not be prepared | vedclass

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Question

(A) The target molecule is $2	ext{-phenylbutan-2-ol}$,which is a tertiary $(3^o)$ alcohol. Option $A$: $HCHO + PhCH(CH_3)CH_2MgX$ gives a primary $(1

Vedclass · Accepted Answer

$HCHO + PhCH(CH_3)CH_2MgX$

Vedclass · Answer

(A) The target molecule is $2	ext{-phenylbutan-2-ol}$,which is a tertiary $(3^o)$ alcohol. Option $A$: $HCHO + PhCH(CH_3)CH_2MgX$ gives a primary $(1^o)$ alcohol,$PhCH(CH_3)CH_2CH_2OH$. Option $B$: $PhCOCH_2CH_3 + CH_3MgX$ gives $CH_3-CH_2-C(Ph)(OH)-CH_3$. Option $C$: $PhCOCH_3 + CH_3CH_2MgX$ gives $CH_3-CH_2-C(Ph)(OH)-CH_3$. Option $D$: $CH_3CH_2COCH_3 + PhMgX$ gives $CH_3-CH_2-C(Ph)(OH)-CH_3$. Thus,option $A$ cannot prepare the target molecule.

$CH_3-CH_2-C(Ph)(OH)-CH_3$ can not be prepared by:

Similar Questions

Primary alcohols can be obtained from the reaction of the $RMgX$ with

In the given reaction,identify $R$ in $RMgBr$:
$CH_3CH_2CHO \xrightarrow[2. H_3O^+]{1. RMgBr} CH_3CH_2CH(OH)CH_2CH_3$

Which reaction will give $CH_3-CH(CH_3)-CH(OH)-CH_3$ as a major product?

$3, 3-$Dimethyl$-2-$butanol cannot be prepared by:
Choose the correct answer from the options given below :

What are $X$ and $Y$ in the following reactions?
$CH_2O \xrightarrow[(ii) H_3O^+]{(i) X} CH_3(CH_2)_2CH_2OH$
$Y \xrightarrow[(ii) H_3O^+]{(i) C_2H_5MgBr} CH_3CH_2C(CH_3)_2OH$

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