p-Hydroxybenzophenone upon reaction with brom | vedclass

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(D) The reaction of $p$-hydroxybenzophenone with $Br_2$ in $CCl_4$ is an electrophilic aromatic substitution reaction.In $p$-hydroxybenzophenone,there

Vedclass · Accepted Answer

$3-$Bromo$-4-$hydroxybenzophenone

Vedclass · Answer

(D) The reaction of $p$-hydroxybenzophenone with $Br_2$ in $CCl_4$ is an electrophilic aromatic substitution reaction.In $p$-hydroxybenzophenone,there are two benzene rings. One ring is attached to a carbonyl group $(-CO-)$,which is an electron-withdrawing group ($-R$ effect),deactivating the ring towards electrophilic aromatic substitution $(EAS)$.The other ring is attached to a hydroxyl group $(-OH)$,which is a strong electron-donating group ($+R$ effect),activating the ring towards $EAS$.The $-OH$ group is ortho/para directing. Since the para position is already occupied by the carbonyl group,the incoming electrophile $(Br^+)$ will attack the ortho position relative to the $-OH$ group.Thus,the product formed is $3$-bromo-$4$-hydroxybenzophenone.

$p$-Hydroxybenzophenone upon reaction with bromine in carbon tetrachloride gives

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