$N_2 + 3H_2 \to 2NH_3$. If the concentration of $NH_3$ changes from $0.01 \ M$ to $0.04 \ M$ in $20 \ seconds$,then the rate of reaction will be:
- A$1.5 \times 10^{-3} \ M \ sec^{-1}$
- B$0.75 \times 10^{-3} \ M \ sec^{-1}$
- C$2 \times 10^{-3} \ M \ sec^{-1}$
- D$3 \times 10^{-3} \ M \ sec^{-1}$
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