50 , mL of 2 , N acetic acid mixed with 10 , | vedclass

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Question

(A) The given solution is an acidic buffer.Meq of acetic acid $(CH_3COOH)$ $= 50 \, mL 	imes 2 \, N = 100 \, meq$.Meq of sodium acetate $(CH_3COONa)$

Vedclass · Accepted Answer

$4$

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(A) The given solution is an acidic buffer.Meq of acetic acid $(CH_3COOH)$ $= 50 \, mL 	imes 2 \, N = 100 \, meq$.Meq of sodium acetate $(CH_3COONa)$ $= 10 \, mL 	imes 1 \, N = 10 \, meq$.Using the Henderson-Hasselbalch equation: $pH = pK_a + \log \frac{[Salt]}{[Acid]}$.$pK_a = -\log(K_a) = -\log(10^{-5}) = 5$.$pH = 5 + \log \frac{10}{100} = 5 + \log(0.1) = 5 - 1 = 4$.

$50 \, mL$ of $2 \, N$ acetic acid mixed with $10 \, mL$ of $1 \, N$ sodium acetate solution will have an approximate $pH$ of $(K_a = 10^{-5})$

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