0.5 g of an organic compound containing phos | vedclass

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(A) The reaction sequence is: $P$ $\xrightarrow{HNO_3} H_3PO_4$ $\xrightarrow{Mg^{2+}, NH_4^+} MgNH_4PO_4$ $\xrightarrow{\Delta} Mg_2P_2O_7$.$1$. Mole

Vedclass · Accepted Answer

$55.85$

Vedclass · Answer

(A) The reaction sequence is: $P$ $\xrightarrow{HNO_3} H_3PO_4$ $\xrightarrow{Mg^{2+}, NH_4^+} MgNH_4PO_4$ $\xrightarrow{\Delta} Mg_2P_2O_7$.$1$. Molecular weight of $Mg_2P_2O_7 = (2 	imes 24.3) + (2 	imes 31) + (7 	imes 16) = 48.6 + 62 + 112 = 222.6 \ g/mol$ (using $222 \ g/mol$ as per standard approximation).$2$. The mass of $P$ in $Mg_2P_2O_7$ is $62 \ g$ per $222 \ g$ of $Mg_2P_2O_7$.$3$. Percentage of $P = \left( \frac{	ext{Mass of } P}{	ext{Mass of } Mg_2P_2O_7} ight) 	imes \left( \frac{	ext{Mass of } Mg_2P_2O_7}{	ext{Mass of organic compound}} ight) 	imes 100$.$4$. Percentage of $P = \left( \frac{62}{222} ight) 	imes \left( \frac{1.0 \ g}{0.5 \ g} ight) 	imes 100 = \left( \frac{62}{222} ight) 	imes 2 	imes 100 = 55.85 \%$.

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